0.01=9y^2

Solution for 0.01=9y^2 equation:

0.01=9y^2

We move all terms to the left:

0.01-(9y^2)=0

a = -9; b = 0; c = +0.01;
Δ = b2-4ac
Δ = 02-4·(-9)·0.01
Δ = 0.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.36}}{2*-9}=\frac{0-\sqrt{0.36}}{-18}
=-\frac{\sqrt{}}{-18}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.36}}{2*-9}=\frac{0+\sqrt{0.36}}{-18}
=\frac{\sqrt{}}{-18}
$